Optimal. Leaf size=124 \[ \frac {c x}{e^3}-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}+\frac {\left (9 c d^2-e (5 b d-a e)\right ) x}{8 d e^3 \left (d+e x^2\right )}-\frac {\left (15 c d^2-e (3 b d+a e)\right ) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{8 d^{3/2} e^{7/2}} \]
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Rubi [A]
time = 0.09, antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {1271, 1171,
396, 211} \begin {gather*} -\frac {\text {ArcTan}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (15 c d^2-e (a e+3 b d)\right )}{8 d^{3/2} e^{7/2}}+\frac {x \left (9 c d^2-e (5 b d-a e)\right )}{8 d e^3 \left (d+e x^2\right )}-\frac {x \left (a e^2-b d e+c d^2\right )}{4 e^3 \left (d+e x^2\right )^2}+\frac {c x}{e^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 211
Rule 396
Rule 1171
Rule 1271
Rubi steps
\begin {align*} \int \frac {x^2 \left (a+b x^2+c x^4\right )}{\left (d+e x^2\right )^3} \, dx &=-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}-\frac {\int \frac {-c d^2+b d e-a e^2+4 e (c d-b e) x^2-4 c e^2 x^4}{\left (d+e x^2\right )^2} \, dx}{4 e^3}\\ &=-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}+\frac {\left (9 c d^2-e (5 b d-a e)\right ) x}{8 d e^3 \left (d+e x^2\right )}+\frac {\int \frac {-7 c d^2+e (3 b d+a e)+8 c d e x^2}{d+e x^2} \, dx}{8 d e^3}\\ &=\frac {c x}{e^3}-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}+\frac {\left (9 c d^2-e (5 b d-a e)\right ) x}{8 d e^3 \left (d+e x^2\right )}-\frac {\left (15 c d^2-e (3 b d+a e)\right ) \int \frac {1}{d+e x^2} \, dx}{8 d e^3}\\ &=\frac {c x}{e^3}-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}+\frac {\left (9 c d^2-e (5 b d-a e)\right ) x}{8 d e^3 \left (d+e x^2\right )}-\frac {\left (15 c d^2-e (3 b d+a e)\right ) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{8 d^{3/2} e^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.07, size = 122, normalized size = 0.98 \begin {gather*} \frac {c x}{e^3}-\frac {\left (c d^2-b d e+a e^2\right ) x}{4 e^3 \left (d+e x^2\right )^2}+\frac {\left (9 c d^2-5 b d e+a e^2\right ) x}{8 d e^3 \left (d+e x^2\right )}-\frac {\left (15 c d^2-3 b d e-a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{8 d^{3/2} e^{7/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.16, size = 106, normalized size = 0.85
method | result | size |
default | \(\frac {c x}{e^{3}}+\frac {\frac {\frac {e \left (a \,e^{2}-5 d e b +9 c \,d^{2}\right ) x^{3}}{8 d}+\left (-\frac {1}{8} a \,e^{2}-\frac {3}{8} d e b +\frac {7}{8} c \,d^{2}\right ) x}{\left (e \,x^{2}+d \right )^{2}}+\frac {\left (a \,e^{2}+3 d e b -15 c \,d^{2}\right ) \arctan \left (\frac {e x}{\sqrt {d e}}\right )}{8 d \sqrt {d e}}}{e^{3}}\) | \(106\) |
risch | \(\frac {c x}{e^{3}}+\frac {\frac {e \left (a \,e^{2}-5 d e b +9 c \,d^{2}\right ) x^{3}}{8 d}+\left (-\frac {1}{8} a \,e^{2}-\frac {3}{8} d e b +\frac {7}{8} c \,d^{2}\right ) x}{e^{3} \left (e \,x^{2}+d \right )^{2}}-\frac {\ln \left (e x +\sqrt {-d e}\right ) a}{16 e \sqrt {-d e}\, d}-\frac {3 \ln \left (e x +\sqrt {-d e}\right ) b}{16 e^{2} \sqrt {-d e}}+\frac {15 d \ln \left (e x +\sqrt {-d e}\right ) c}{16 e^{3} \sqrt {-d e}}+\frac {\ln \left (-e x +\sqrt {-d e}\right ) a}{16 e \sqrt {-d e}\, d}+\frac {3 \ln \left (-e x +\sqrt {-d e}\right ) b}{16 e^{2} \sqrt {-d e}}-\frac {15 d \ln \left (-e x +\sqrt {-d e}\right ) c}{16 e^{3} \sqrt {-d e}}\) | \(217\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.52, size = 114, normalized size = 0.92 \begin {gather*} c x e^{\left (-3\right )} - \frac {{\left (15 \, c d^{2} - 3 \, b d e - a e^{2}\right )} \arctan \left (\frac {x e^{\frac {1}{2}}}{\sqrt {d}}\right ) e^{\left (-\frac {7}{2}\right )}}{8 \, d^{\frac {3}{2}}} + \frac {{\left (9 \, c d^{2} e - 5 \, b d e^{2} + a e^{3}\right )} x^{3} + {\left (7 \, c d^{3} - 3 \, b d^{2} e - a d e^{2}\right )} x}{8 \, {\left (d x^{4} e^{5} + 2 \, d^{2} x^{2} e^{4} + d^{3} e^{3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 415, normalized size = 3.35 \begin {gather*} \left [\frac {30 \, c d^{4} x e + 2 \, a d x^{3} e^{4} - {\left (a x^{4} e^{4} - 15 \, c d^{4} + {\left (3 \, b d x^{4} + 2 \, a d x^{2}\right )} e^{3} - {\left (15 \, c d^{2} x^{4} - 6 \, b d^{2} x^{2} - a d^{2}\right )} e^{2} - 3 \, {\left (10 \, c d^{3} x^{2} - b d^{3}\right )} e\right )} \sqrt {-d e} \log \left (\frac {x^{2} e - 2 \, \sqrt {-d e} x - d}{x^{2} e + d}\right ) + 2 \, {\left (8 \, c d^{2} x^{5} - 5 \, b d^{2} x^{3} - a d^{2} x\right )} e^{3} + 2 \, {\left (25 \, c d^{3} x^{3} - 3 \, b d^{3} x\right )} e^{2}}{16 \, {\left (d^{2} x^{4} e^{6} + 2 \, d^{3} x^{2} e^{5} + d^{4} e^{4}\right )}}, \frac {15 \, c d^{4} x e + a d x^{3} e^{4} + {\left (a x^{4} e^{4} - 15 \, c d^{4} + {\left (3 \, b d x^{4} + 2 \, a d x^{2}\right )} e^{3} - {\left (15 \, c d^{2} x^{4} - 6 \, b d^{2} x^{2} - a d^{2}\right )} e^{2} - 3 \, {\left (10 \, c d^{3} x^{2} - b d^{3}\right )} e\right )} \sqrt {d} \arctan \left (\frac {x e^{\frac {1}{2}}}{\sqrt {d}}\right ) e^{\frac {1}{2}} + {\left (8 \, c d^{2} x^{5} - 5 \, b d^{2} x^{3} - a d^{2} x\right )} e^{3} + {\left (25 \, c d^{3} x^{3} - 3 \, b d^{3} x\right )} e^{2}}{8 \, {\left (d^{2} x^{4} e^{6} + 2 \, d^{3} x^{2} e^{5} + d^{4} e^{4}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 1.37, size = 201, normalized size = 1.62 \begin {gather*} \frac {c x}{e^{3}} - \frac {\sqrt {- \frac {1}{d^{3} e^{7}}} \left (a e^{2} + 3 b d e - 15 c d^{2}\right ) \log {\left (- d^{2} e^{3} \sqrt {- \frac {1}{d^{3} e^{7}}} + x \right )}}{16} + \frac {\sqrt {- \frac {1}{d^{3} e^{7}}} \left (a e^{2} + 3 b d e - 15 c d^{2}\right ) \log {\left (d^{2} e^{3} \sqrt {- \frac {1}{d^{3} e^{7}}} + x \right )}}{16} + \frac {x^{3} \left (a e^{3} - 5 b d e^{2} + 9 c d^{2} e\right ) + x \left (- a d e^{2} - 3 b d^{2} e + 7 c d^{3}\right )}{8 d^{3} e^{3} + 16 d^{2} e^{4} x^{2} + 8 d e^{5} x^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 4.89, size = 107, normalized size = 0.86 \begin {gather*} c x e^{\left (-3\right )} - \frac {{\left (15 \, c d^{2} - 3 \, b d e - a e^{2}\right )} \arctan \left (\frac {x e^{\frac {1}{2}}}{\sqrt {d}}\right ) e^{\left (-\frac {7}{2}\right )}}{8 \, d^{\frac {3}{2}}} + \frac {{\left (9 \, c d^{2} x^{3} e - 5 \, b d x^{3} e^{2} + 7 \, c d^{3} x + a x^{3} e^{3} - 3 \, b d^{2} x e - a d x e^{2}\right )} e^{\left (-3\right )}}{8 \, {\left (x^{2} e + d\right )}^{2} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.39, size = 118, normalized size = 0.95 \begin {gather*} \frac {c\,x}{e^3}-\frac {x\,\left (-\frac {7\,c\,d^2}{8}+\frac {3\,b\,d\,e}{8}+\frac {a\,e^2}{8}\right )-\frac {x^3\,\left (9\,c\,d^2\,e-5\,b\,d\,e^2+a\,e^3\right )}{8\,d}}{d^2\,e^3+2\,d\,e^4\,x^2+e^5\,x^4}+\frac {\mathrm {atan}\left (\frac {\sqrt {e}\,x}{\sqrt {d}}\right )\,\left (-15\,c\,d^2+3\,b\,d\,e+a\,e^2\right )}{8\,d^{3/2}\,e^{7/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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